1 | function tree = copy(tree,subuid,uid) |
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2 | % XMLTREE/COPY Copy Method (copy a subtree in another branch) |
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3 | % FORMAT tree = copy(tree,subuid,uid) |
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4 | % |
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5 | % tree - XMLTree object |
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6 | % subuid - UID of the subtree to copy |
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7 | % uid - UID of the element where the subtree must be duplicated |
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8 | %_______________________________________________________________________ |
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9 | % |
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10 | % Copy a subtree to another branch |
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11 | % The tree parameter must be in input AND in output |
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12 | %_______________________________________________________________________ |
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13 | % @(#)copy.m Guillaume Flandin 02/04/08 |
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14 | |
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15 | error(nargchk(2,3,nargin)); |
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16 | if nargin == 2 |
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17 | uid = parent(tree,subuid); |
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18 | end |
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19 | |
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20 | l = length(tree); |
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21 | tree = sub_copy(tree,subuid,uid); |
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22 | tree.tree{uid}.contents = [tree.tree{uid}.contents l+1]; |
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23 | |
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24 | % pour que la copie soit a cote de l'original et pas a la fin ? |
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25 | % contents = get(tree,parent,'contents'); |
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26 | % i = find(contents==uid); |
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27 | % tree = set(tree,parent,'contents',[contents(1:i) l+1 contents(i+1:end)]); |
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28 | |
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29 | %======================================================================= |
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30 | function tree = sub_copy(tree,uid,p) |
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31 | |
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32 | l = length(tree); |
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33 | tree.tree{l+1} = tree.tree{uid}; |
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34 | tree.tree{l+1}.uid = l+1; |
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35 | tree.tree{l+1}.parent = p; |
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36 | tree.tree{l+1}.contents = []; |
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37 | if isfield(tree.tree{uid},'contents') |
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38 | contents = get(tree,uid,'contents'); |
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39 | m = length(tree); |
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40 | for i=1:length(contents) |
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41 | tree.tree{l+1}.contents = [tree.tree{l+1}.contents m+1]; |
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42 | tree = sub_copy(tree,contents(i),l+1); |
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43 | m = length(tree); |
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44 | end |
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45 | end |
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